Sunday, 21 February 2016

Show XSLT in Table Format new Template

<Xsl>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt"
              exclude-result-prefixes="msxsl" xmlns:ddwrt2="urn:frontpage:internal">
<xsl:output method='html' indent='yes'/>
  <xsl:template match='dsQueryResponse' xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" ddwrt:ghost="" xmlns:ddwrt2="urn:frontpage:internal">

<table id="tbl1" cellpadding="0" cellspacing="0" border="0" style="padding:0px;" class="tableRound" width="1000px">
<tr>
<td style="width:1000px">
<div style="width:1000px; position:relative;vertical-align:top;">
<xsl:apply-templates select='Rows/Row'/>
</div></td></tr>
</table>
</xsl:template>


<xsl:template match='Row'>


<div style="float:left; vertical-align:top; background-color:transparent; width:180px; height:70px; padding-bottom:0px;">
<div style="float:left; width:150px;">

<a class="className" target="_blank">
<xsl:attribute name="href">
<xsl:value-of select="@URL"></xsl:value-of>
</xsl:attribute>
<xsl:value-of select="@URL.desc"></xsl:value-of>
</a>


</div>
</div>

</xsl:template>

</xsl:stylesheet></Xsl>

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